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Four diatomic species are listed in different sequence .Which of these represent the correct order of their increasing bond order?A. `O_2^(-) lt NO lt C_2^(2-) lt He_2^(+)`B. `NO lt C_2^(2-) lt O_2^(-) lt He_2^(+)`C. `C_2^(2-) lt He_2^(+) lt NO lt O_2^(-)`D. `He_2^(+) lt O_2^(-) lt NO lt C_2^(2-)` |
Answer» Correct Answer - D Electronic configuration are `He_2^(2+): (sigma1s)^2(sigma^**1s)^1`, `bo=(2-1)/(2)=1/2=0.5` `O_2^(-):KK(sigma2s)^2(sigma^**2s)^2(sigma2p_z)^2(pi2p_x^2=pi2p_y^2)(pi^**2p_x^2=pi^**2p_y^1)` `bo=(10-7)/(2)=1.5` `NO:KK(sigma2s)^2(sigma^**2s)^2(sigma2p_z)^2(pi2p_x^2=pi2p_y^2)(pi^**2p_x^1=pi^**2p_y^0)` `bo=(10-5)/(2)=2.5` `C_2^(2-):KK(sigma2s)^2(sigma^**2s)^2(pi2p_x^2=pi2p_y^2)(sigma2p_z)^2` `bo=(10-4)/(2)=3.0` Thus, the correct order of increasing bond order is `He_2^(+) lt O_2^(-) lt NO lt C_2^(2-)` |
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