InterviewSolution
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InterviewSolution
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Four diatomic species are listed in different sequence .Which of these represent the correct order of their increasing bond order?A. `O_2^(-) lt NO lt C_2^(2-) lt He_2^+`B. `NO lt C_2^(2-) lt O_2^(-) lt He_2^(+)`C. `C_2^(2-) lt He_2^(+) lt NO lt O_2^(-)`D. `He_2^(+) lt O_2^(-) lt NO lt C_2^(2-)` |
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Answer» Correct Answer - D The molecular orbital configuration of `O_2^-` (8+8+1=17)=`sigma1s^2,overset***sigma1s^2,sigma2s^2,overset***sigma2s^2,sigma2p_x^2,pi2p_y^2~~pi2p_z^2,overset***2p_y^2~~overset***pi2p_z^1` Bond order (BO)=`(N_b-N_a)/2=(10-7)/2=1.5` `NO` (7+8=15)=`sigma1s^2,overset***sigma1s^2,sigma2s^2,overset***sigma2s^2,sigma2p_x^2,pi2p_y^1~~pi2p_z^0` Bond order (BO)=`(10-5)/2=2.5` `C_2^(2-)` (6+6+2=14)=`sigma1s^2,overset***sigma1s^2,sigma2s^2,overset***sigma2s^2,pi2p_y^2~~pi2p_z^2,overset***2p_x^2` Bond order (BO)=`(10-4)/2=3` `He_2^+` (2+2-1=3) =`sigma1s^2, overset***1s^1` BO`=(2-1)/2=1/2=0.5` Hence, order of increasing bond order is `He_2^(+) lt O_2^(-) lt NO lt C_2^(2-)` |
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