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Four equal charges each 16 muC are placed on four corners of a squareof side 0.4m. Calculateforce on q is zero, how are Q and q related ? |
Answer»  Refer to Fig. `AB = BC = CD = AD = 0.4m`. Force exerted by `q_(4) on q_(1)` = force exerted by `q_(2)` on `q_(1)` `F_(1) = F_(3) = (9XX10^(9)xx16xx10^(-6)xx16xx10^(-6))/((0.4)^(2)) = 14.4 N` Force EXERTEDBY `q_(3)` on `q_(1)` `F_(2) = (9xx10^(9)xx16xx10^(-6)xx16xx10^(-6))/((0.4)^(2) + (0.4)^(2)) = 7.2 N` `F_(1) and F_(3)` are perpendicular to each other, resultant force `F = sqrt( F_(1)^(2) + F_(3)^(2)) = sqrt((14.4)^(2) + (14.4)^(2)) = 20.36 N` Total force on `q_(1) = F + F_(2) = 20.36 + 7.2` `=27.56N` |
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