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Four equal masses (each of mass M) are placed at the corners of a squares side a the escape velocity of a body from the centre O of the square isA. `4sqrt(2GM)/(a)`B. `sqrt(8sqrt(2GM))/(a)`C. `(4GM)/(a)`D. `sqrt(4sqrt(2)GM)/(a)` |
Answer» Correct Answer - B Potential at centre `=-(4GM)/(r )=(-4GM)/(a//sqrt(2))=-(4sqrt(2)GM)/(a)` `PE=(-4sqrt(2)GMm)/(a)` `BE=(4sqrt(2)GMm)/(a)` `therefore 1/2mv_(e)^(2)=(4sqrt(2)GMm)/(a)` `rarr v_(e )=sqrt(8sqrt(2)GM)/(a)` |
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