1.

Four grams of graphite is burnt in a bomb calorimeter of heat capacity 30 kJ K^(-1) in excess of oxygen at 1 atmospheric pressure. The temperature rises from 300 to 304 K. What is the enthalpy of combustion of graphite (in kJ mol^(1)) ?

Answer»

360
1440
`-360`
`-1440`

Solution :`Delta E = C xx Delta t xx (M)/(m)`
`= 30 kJ K^(-1) xx 4 xx (12)/(4)`
`= 360 kJ mol^(-1)`
`Delta E = -360 kJ mol^(-1)`


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