1.

Four grams of graphite is burnt in a bomb calorimeter of heat capacity 30 kJ K^(-1) in excess of oxygen at 1 atmospheric pressure. The temperature rises from 300 to 304 K. What is the enthalpy of combustion of graphite (in kJ mol^(-1))

Answer»

360
1440
`- 360`
`- 1440`

Solution :`DeltaE=CxxDeltatxx(M)/(m)=30xx4xx(12)/(4)=360`
`DeltaE=-360 KJ mol^(-1)`


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