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Four identical spheres each of radius 'a' are placed on a horizontal table touching one another so that their centres lie at the corners of a square of side 2a. Position of their centre of mass is : |
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Answer» 2A, a  `X=(Mxx0+Mxx2a+M(2a)+Mxx0)/(M+M+M+M)=a` Then `y=(Mxx0+Mxx0+Mxx2a+Mxx2a)/(M+M+M+M)=a` |
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