1.

Four lowest energy levels of `H`-atom are shown in the figure. The number of possoble emission lines would be A. `3`B. `4`C. `5`D. `6`

Answer» Correct Answer - D
Number of possible emission lines `= (n(n - 1))/(2)`
where `n = 4`, Number `= (4(4 - 1))/(2) = 6`


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