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1. |
Four lowest energy levels of `H`-atom are shown in the figure. The number of possoble emission lines would be A. `3`B. `4`C. `5`D. `6` |
Answer» Correct Answer - D Number of possible emission lines `= (n(n - 1))/(2)` where `n = 4`, Number `= (4(4 - 1))/(2) = 6` |
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