InterviewSolution
Saved Bookmarks
| 1. |
Four MFR’s are operated in series the total space time is 5 minutes. If it is replaced by a single PFR, What will be the space time? First order reaction with rate constant 2 min^-1, concentration reduces from 50 to 10 mol/m^3.(a) 0.805(b) 0.123(c) 0562(d) 0.439I have been asked this question in my homework.This interesting question is from Choosing of Right Reactor Series or Connections (Maximum Profitability) in division Ideal Reactors for a Single Reaction, Conversion and Reactor Sizing of Chemical Reaction Engineering |
|
Answer» CORRECT OPTION is (a) 0.805 Easy EXPLANATION: The design equation of PFR is τ = \(\int_{CA0}^{CAf}\frac{-dCA}{-rA} \) For the 1^st ORDER reaction the equation is simplified as kτ = -ln(\(\frac{CA}{CA0}\)) τ = -0.5ln(\(\frac{10}{50}\)) = 0.805 MINUTES. |
|