1.

Four moles of carbon monoxide anre mixed with four moles of carbon dioxide. Asuming the gases to be ideal, the ratio of specific heats is :

Answer»

`15//11`
`41//30`
`4//3`
`7//4`

SOLUTION :The value of ratio of specific heats of mixture
`gamma =(n_(1)C_(p1)+n_(2)C_(P2))/(n_(1)C_(v1)+n_(2)C_(v2))`
As `C_(p) and C_(v)` of DIATOMIC gas have values `(7R)/(2) and (5R)/(2)`
whereas their values for polyatomic gas are 4R and 3R.
So on substituting these values we get
`gamma =(15)/(11)`.
Correct choice is (a).


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