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Four pairs of numbers have been given, out of which three are alike in some manner, while one is different. Choose out the odd one.1. 25 : 144 : 172. 121 : 49 : 193. 196 : 1 : 154. 9 : 361 : 22 |
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Answer» Correct Answer - Option 2 : 121 : 49 : 19 The pattern followed here is: Square root of 1st term + Square root of 2nd term = Third term Option 1 → √25 + √144 = 5 + 12 = 17 Option 2 → √121 + √49 = 11 + 7 = 18 ≠ 19 Option 3 → √196 + √1 = 14 + 1 = 15 Option 4 → √9 + √361 = 3 + 19 = 22 Hence, '121 : 49 : 19' is the odd pair. |
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