Four particles each of mass m are placed at the vertices of a square of side l. the potential at the centre of square isA. `-sqrt(32)(GM)/L`B. `-sqrt(64)(GM)/(L^(2))`C. zeroD. `-sqrt(16)(GM)/L`

Four particles each of mass m are placed at the vertices of a square o

1.	Four particles each of mass m are placed at the vertices of a square of side l. the potential at the centre of square isA. `-sqrt(32)(GM)/L`B. `-sqrt(64)(GM)/(L^(2))`C. zeroD. `-sqrt(16)(GM)/L`
Answer» Correct Answer - A `U=-4(GM)/(L//sqrt(2))=-sqrt(32)(GM)/L`

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Four particles each of mass m are placed at the vertices of a square of side l. the potential at the centre of square isA. `-sqrt(32)(GM)/L`B. `-sqrt(64)(GM)/(L^(2))`C. zeroD. `-sqrt(16)(GM)/L`

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