1.

Four particles have speed `2, 3, 4` and 5 cm/s respectively Their `RMS` speed is .A. 3.5 cm/sB. (27/2) cm/sC. `sqrt(54)` cm/sD. `sqrt(54) //2` cm/s

Answer» Correct Answer - d
(d) `U_("rms")=sqrt((U_(1)^(2)+U_(2)^(2)+U_(3)^(2)+U_(4)^(2))/(4))=sqrt((54)/(2))=(sqrt(54))/(2)`


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