Four particles of masses 1 kg, 2 kg, 3 kg and 4 kg are at the vertices of a rectangle of sides a and b with agtb. If a = 1 m, b = 2 m, what is the location of their centre of mass ?

Four particles of masses 1 kg, 2 kg, 3 kg and 4 kg are at the vertices

1.	Four particles of masses 1 kg, 2 kg, 3 kg and 4 kg are at the vertices of a rectangle of sides a and b with agtb. If a = 1 m, b = 2 m, what is the location of their centre of mass ?
Answer» 0.5 m, 1.4 m 1.4 m, 0.5 m 0.14 m, 0.05 m 0.05 m, 0.14 m SOLUTION :Here `vecx=(Sigmam_(1)x_(1))/(M)` `=(1)/(10)(0xx1+2xxa+3xxa+4xx0)=0.5m` `VECY=(Sigmam_(1)x_(1))/(M)` `=(1)/(10)(0xx1+2xx0+3xxb+4xxb)` = 1.4 m

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Four particles of masses 1 kg, 2 kg, 3 kg and 4 kg are at the vertices of a rectangle of sides a and b with agtb. If a = 1 m, b = 2 m, what is the location of their centre of mass ?

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