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Four pieces of string of length L are joined end to end to make a long string of length 4L. The linear mass density of the strings are `mu,4mu,9mu and 16mu`, respectively. One end of the combined string is tied to a fixed support and a transverse wave has been generated at the other end having frequency `f` (ignore any reflection and absorption). string has been stretched under a tension `F`. Find the ratio of wavelength of the wave on four string, starting from right hand side.A. `12:6:4:3`B. `4:3:2:1`C. `3:4:6:12`D. `1:2:3:4`

Answer» Correct Answer - c
Frequency of wave is same on all the four string. So,
`lambda_(1)=(v_(1))/(f), lambda_(2)=(v_(2))/(f)`
`lambda_(3)=(v_(3))/(f) lambda_(4)=(v_(4))/(f)`
`lambda_(4), lambda_(3), lambda_(2), lambda_(1)=(1)/(40:(1)/(3):(1)/(2):1=3:4:6:12`


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