1.

Four point masses, each of value m, are placed at the corners of a square ABCD of side l. The moment of inertia of this system about an axis passing through A are parallel to BD is :

Answer»

`2m//l^(2)`
`sqrt(3)ML^(2)`
`3ML^(2)`
`ml^(2)`

SOLUTION :
`I_(LM)=m_(A)(0)^(2)+m_(B)((lsqrt(2))/(2))^(2)+m_(C)(lsqrt(2))^(2)+m_(D)((lsqrt(2))/(2))^(2)`
`I_(LM)=0+(ml^(2))/(2)+2ml^(2)+(ml^(2))/(2)=3ml^(2)`


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