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Four resistors, 100 Omega, 200 Omega, 300 Omega and 400 Omega are connected to form four sides of a square. The resistors can be connected in any order. What is the maximum possible equivalent resistance across the diagonal of the square? |
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Answer» `210 Omega` ` therefore ` Equivalent resistance, `R_1 = 2R + 3R = 5R ` ALSO, R and 4R are in series their equivalent resistance will be, `R_2 = R +4 R= 5R `  Now` R_1 and R_2`are in parallelhencemaximumequivalentresistance ` R_(eq) = (R_1 + R_2)/( R_1 + R_2) = 5/2xx 100= 250Omega ` |
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