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Four vessels A,B,C and D contain respectively 20g atom (T_(1//2)=5h) 2g atom (T_(1//2)= 1h)5g atom(T_(1//2)=2h) and 10g atom (T_(1//2)=3h) of different radio nuclides in the beginning , the maximum activity would be exhibited by the vessel is |
| Answer» SOLUTION :`R = lamdaN=(0.693)/(T_(1//2)) N` HENCE , GREATER `(N/(T_(1//2)))` value , grater will be the rate . So A has MAXIMUM activity. | |