1.

Four voice signals. each limited to 4 kHz and sampled at Nyquist rate are converted into binary PCM signal using 256 quantization levels. The bit transmission rate for the time-division multiplexed signal will be(a) 8 kbps(b) 64 kbps(c) 256 kbps(d) 512 kbpsI got this question during an online exam.Origin of the question is Digital Transmission in division EDC Overview of Electronic Devices & Circuits

Answer»

The CORRECT ANSWER is (c) 256 kbps

To elaborate: NYQUIST RATE2 x 4k = 8 kHz

Total SAMPLE 4 x 8 = 32 k sample/sec

256 = 2^8, so that 8 bits are required

Bit Rate32k x 8 = 256 kbps.



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