\((\frac{1}{64})^0 + (64)^{\frac{-1}{2}}+(32)^{\frac{4}{5}}-(32)^{\fra

1.	\((\frac{1}{64})^0 + (64)^{\frac{-1}{2}}+(32)^{\frac{4}{5}}-(32)^{\frac{-4}{5}}\) is equal to (a) \(16\frac18\)(b) \(17\frac18\)(c) \(17\frac1{16}\)(d) \(-17\frac1{16}\)
Answer» (c) \(17\frac1{16}\) Given exp. = 1 + \((8^2)^{-\frac12}+(2^5)^{\frac45}-(2^5)^{-\frac45}\) = 1 + 8^–1 + 2⁴ – 2^–4 = \(1+ \frac18+16-\frac1{16}=\frac{16+2+256-1}{16}\) ^{= \(\frac{273}{16} = 17\frac1{16}\)}

\((\frac{1}{64})^0 + (64)^{\frac{-1}{2}}+(32)^{\frac{4}{5}}-(32)^{\frac{-4}{5}}\) is equal to (a) \(16\frac18\)(b) \(17\frac18\)(c) \(17\frac1{16}\)(d) \(-17\frac1{16}\)

Answer»

(c) \(17\frac1{16}\)

Given exp. = 1 + \((8^2)^{-\frac12}+(2^5)^{\frac45}-(2^5)^{-\frac45}\)

= 1 + 8^–1 + 2⁴ – 2^–4

= \(1+ \frac18+16-\frac1{16}=\frac{16+2+256-1}{16}\)

^{= \(\frac{273}{16} = 17\frac1{16}\)}