\(\frac{{5}^{n+2}-{6} \times {5}^{n+1}}{{13 \times{5}^n-2 \times{5}^{n

1.	\(\frac{{5}^{n+2}-{6} \times {5}^{n+1}}{{13 \times{5}^n-2 \times{5}^{n+1}}}\)is equal toA. \(\frac{5}3\)B. \(-\frac{5}3\)C. \(\frac{3}5\)D. \(-\frac{3}5\)
Answer» 5ⁿ (25 – 30) / 5ⁿ (13 – 10) = -5 / 3

\(\frac{{5}^{n+2}-{6} \times {5}^{n+1}}{{13 \times{5}^n-2 \times{5}^{n+1}}}\)is equal toA. \(\frac{5}3\)B. \(-\frac{5}3\)C. \(\frac{3}5\)D. \(-\frac{3}5\)

Answer»

5ⁿ (25 – 30) / 5ⁿ (13 – 10)

= -5 / 3