\(\frac{7!}{5!}\) = ____________________(a) 7(b) 42(c) 230(d) 30The question was posed to me in final exam.The query is from Permutations-1 in portion Permutations and Combinations of Mathematics – Class 11

\(\frac{7!}{5!}\) = ____________________(a) 7(b) 42(c) 230(d) 30The qu

1.	\(\frac{7!}{5!}\) = ____________________(a) 7(b) 42(c) 230(d) 30The question was posed to me in final exam.The query is from Permutations-1 in portion Permutations and Combinations of Mathematics – Class 11
Answer» The CORRECT answer is (b) 42 To explain I would say: We know, N! = n.(n-1).(n-2).(n-3)…… = n(n-1)! \(\FRAC{7!}{5!} = \frac{7.6!}{5!} = \frac{7.6.5!}{5!}\) = 7.6 = 42.

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