1.

\frac{\sec ^{2} \frac{\pi}{4}-\cot ^{2} \frac{\pi}{4}}{\sin ^{2} \frac{\pi}{3}+\cos ^{2} \frac{\pi}{6}}+\frac{\sin ^{2} \frac{\pi}{2}-\cos ^{2} \frac{\pi}{3}}{\frac{1}{4} \tan ^{2} \frac{\pi}{6}}=9 \frac{2}{3}

Answer» <p>(sec pie/4*sec pie/4-cot pie/4*cot pie/4) / (sin pie/3*sin pie/3 + cos pie/6*cos pie/6) + (sin pie/2*sin pie/2 - cos pie/3*cos pie/3) / (1/4tan pie/6*tan pie/6) = (2-1)/(3/4+3/4) + (1-1/4)/(1/4×3) = (1)/(3/2) - (3/4)/(3/4) = 29/3 = 9 2/3 </p>


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