1.

Fraunhoffer diffraction experiment at a single slit using light of wavelength 400 mm, the first minima is formed at an angle of 30^(@). Then the direction theta of the first secondary maximum is given by :

Answer»

`tan^(-1)(3/4)`
`SIN^(-1)(3/4)`
`60^(@)`
`tan^(-1)(4/3)`

SOLUTION :Using `d = (lambda) /(sin theta)`, we get,
`d = (400 xx 10^(-9))/(sin 30^(@)) = (400 xx 10^(-9))/(1/2)= 8 xx 10^(-7) m`
Again `d sin theta = (3 lambda)/(2)` i.e. `sin theta = (3lambda)/(2a) = (3 xx 4 xx 10^(-7))/(2 xx 8 xx 10^(-7)) = 3/4`
i.e.`theta= sin^(-1)3/4`


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