1.

Frequency and wavelength of light in transparent material are 2xx10^(14) Hz and 5000 Å respectively, then its refractive index is

Answer»

`1.50`
`3.00`
1.33
`1.40`

Solution :By USING v=f`lambda`
`v=2xx10^(14)xx5000xx10^(-10)` m
`=10^8 MS^(-1)`
`lambda=5000` Å
`=5000xx10^(-10)` m
Refractive INDEX `mu=c/v=(3xx10^8)/(10^8)`
`therefore mu=3`


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