InterviewSolution
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InterviewSolution
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Frequency of a particle executing SHM is 10 Hz. The particle is suspended from a vertical spring. At the highest point of its oscillation the spring is unstretched. Maximum speed of the particle is `(g=10(m)/(s))`A. `2pi(m)/(s)`B. `pi(m)/(s)`C. `(1)/(pi)(m)/(s)`D. `(1)/(2pi)/(m)/(s)` |
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Answer» Correct Answer - D Mean position of the particle is `(mg)/(k)` distance below the unstretched position of spring. Therefore aplitude of oscillation `A=(mg)/(k)` `omega=sqrt((k)/(m))=2pif=20pi(f=10Hz)` `(m)/(k)=(1)/(400pi^2)` `v_(max)=Aomega=(g)/(400pi^2)xx20pi=(1)/(2pi)(m)/(s)` |
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