1.

Frequency of photon having 100 eV energy is ……Hz [h=6.62xx10^(-34)Js,1eV=1.6xx10^(-19)Js]

Answer»

`2.417xx10^(-16)`
`2.417xx10^(16)`
`2.417xx10^(17)`
`1.054xx10^(17)`

Solution :E=hf
`THEREFORE f=(E )/(h)=(100xx1.6xx10^(-19))/(6.62xx10^(-34))`
`=24169xx10^(17)`
`~~2.417xx10^(16)`Hz


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