1.

Frequency of photon having 66 eV energy will be……(h=6.6xx10^(-34)Js)

Answer»

`8XX10^(-15)Hz`
`12XX10^(-15)Hz`
`16xx10^(-15)Hz`
`24xx10^(-15)Hz`

Solution :E=hf
`therefore F=(E )/(H)=(66.1.6xx10^(-19))/(6.6xx10^(-34))=16xx10^(-15)Hz`


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