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From a circular card sheet of radius 14 cm, two circles of radius 3.5 cm and arectangle of length 3 cm and breadth 1cm are removed. (as shown in the adjoining Figure). Find the area of the remaining sheet. (Take π=22/7) |
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Answer» R=14 cmtotal area= πr²=22/7*196=616 cm²r2= 3.5 cmarea of the small circles= 2*πr²=2*12.25*22/7=77 cm²length of rectangle=3breadth=1area =lb=3 cm² area of the small circles+area of rectangle=77+3=80 cm² remaining area=616-80=536 cm² |
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