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From a tower of height H, a particle is thrown vertically upwards with a speed u. The time taken by the particle, to hit the ground, is n times that taken by it to reach the highest point of its path. The relation between H, u and n is : |
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Answer» `GH=(n-2)u^(2)` If `t_(2)` be the time taken to hit the ground, then `-H=ut_(2)-1/2g t_(2)^(2)` But `t_(2)=nt_(1)`(given) `implies-H=u(nu)/g-1/2g(n^(2)u^(2))/g^(2)implies2gH=nu^(2)(n-2)` |
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