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From an external point P, tangents PA and PB are drawn to a circle with centre 0. If ∠PAB = 50°, then find ∠AOB? ★ REQUIRED QUALITY ANSWER |
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Answer» -step explanation:ANSWERGIVEN, PA=PB, and ∠PAB=50 o To PROVE: Measure of ∠AOBProof: PA=PB (∵ given)∠PBA=∠PAB (∵ angle opposite sides are EQUAL)∴∠PBA=50 o .In ΔPAB∠PBA+∠PAB+∠APB=180 o (∵ A.S.P)∠APB=180 o −100 o ∠APB=80 o ∠AOB+∠APB=180 o (∴ supplementary ANGLES)∠AOB=180 o −80 o ∠AOB=100 o ∴ Hence proved.stay safe✌Hit the❤ |
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