1.

From figure, find the work done at the end of displacements: (a) 20cm, (b) 40cm, and (c) 80cm.

Answer» a. Work done at the end of displacement `20cm`,
=Area of triangle OAM
`=1/2xx(20xx10^-2)xx10=1J`
b. Work done at the end of displacement `40cm`,
=Area of OABN
=Area of OAM+Area of rectangle ABMN
`=1+20xx10^-2xx10=3J`
c. Work done at the end of displacement `80cm`,
=Area of trapezium OACR-Area of rectangle RQD
`=1/2(60+30)xx10^-2xx10-1/2xx(20xx10^-2)xx10`
`=3.5J`
Net area from `50cm` to `60cm` will be zero.


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