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From figure, find the work done at the end of displacements: (a) 20cm, (b) 40cm, and (c) 80cm. |
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Answer» a. Work done at the end of displacement `20cm`, =Area of triangle OAM `=1/2xx(20xx10^-2)xx10=1J` b. Work done at the end of displacement `40cm`, =Area of OABN =Area of OAM+Area of rectangle ABMN `=1+20xx10^-2xx10=3J` c. Work done at the end of displacement `80cm`, =Area of trapezium OACR-Area of rectangle RQD `=1/2(60+30)xx10^-2xx10-1/2xx(20xx10^-2)xx10` `=3.5J` Net area from `50cm` to `60cm` will be zero. |
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