InterviewSolution
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From source of power 4 kW,radiation emitted are such that photon are emitted at rate of 10^(20) photon/sec.This radiation will be in …..region of electromagnetic waves… []h=6.6xx10^(-34)Js |
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Answer» gamma rays `therefore F=(p)/((n)/(t)h)=(4000)/(10^(20)xx6.6xx10^(-34))` `=6.06xx10^(16)HZ` The spectrum containing frequency are of X-region. |
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