From the following bond energies H-H bond energy : 431.37 kJ mol^(-1)C=C bond energy : 606.10 kJ mol^(-1)C-C bond energy : 336.49 kJ mol^(-1) C-H bond energy : 410.50 kJ mol^(-1) Enthalpy for the reaction. underset(H)underset(|)overset(H)overset(|)(C)=underset(H)underset(|)overset(H)overset(|)(C)+H-HrarrH-underset(H)underset(|)overset(H)overset(|)(C)-underset(H)underset(|)overset(H)overset(|)(C)-H will be

From the following bond energies H-H bond energy : 431.37 kJ mol^(-1)

1.	From the following bond energies H-H bond energy : 431.37 kJ mol^(-1)C=C bond energy : 606.10 kJ mol^(-1)C-C bond energy : 336.49 kJ mol^(-1) C-H bond energy : 410.50 kJ mol^(-1) Enthalpy for the reaction. underset(H)underset(\|)overset(H)overset(\|)(C)=underset(H)underset(\|)overset(H)overset(\|)(C)+H-HrarrH-underset(H)underset(\|)overset(H)overset(\|)(C)-underset(H)underset(\|)overset(H)overset(\|)(C)-H will be
Answer» 1523.6 KJ `MOL^(-1)` `-243.6 kJ mol^(-1)` `-120.0 kJ mol^(-1)` 553.0 kJ `mol^(-1)` SOLUTION :`[(4xx410.5)xx606.1+431.3)]-[(6xx410.5)+336.49)]` `=-120.0 kJ mol^(-1)`.