1.

From the following bond energies : {:(H-H "bond energy :" 431.37 kJ mol^(-1)),(C=C "bond energy :" 606.10 kJ mol^(-1)),(C-C "bond energy : "336.49 kJmol^(-1)),(C-H "bond energy :" 410.50kJ mol^(-1)):} calculate the bond energy of the following reaction : H-overset(overset(H)(|))( C)= overset(overset(H)(|))(C )-H + H - H rarr H - underset(underset(H)(|))overset(overset(H)(|))(C )- underset(underset(H)(|))overset(overset(H)(|))(C)- H

Answer»

`- 243.6 KJ//mol`
`- 120.0 kJ//mol`
553.0 kJ//mol
1523.6 kJ//mol

Solution :`Delta_(f) H = B.E_("reactants") - B.E_("PRODUCTS")`
`= [B.E_(C = C) + B.E_(H - H) + 4 xx B.E_(C - H)]`
`= [B.E_(C - C) + 6 xx B.E_(C - H)]`
`= (606.10 + 431.37 + 4 xx 410.5) - (336.49 + 6 xx 410.50)`
`= - 120.2 kJ mol^(-1)`


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