InterviewSolution
Saved Bookmarks
| 1. |
From the following data at `25^(@)C`, Calculate the standard enthalpy of formation of `FeO(s)` and of `Fe_(2)O_(3) (s)`. `{:(,"Reaction",Delta_(r)H^(@)" (kJ/mole)"),((1),Fe_(2)O_(3)(s)+3C ("graphite") rarr 2Fe(s) +3CO(g),492.6),((2),FeO(s)+C("graphite") rarr Fe(s)+CO(g),155.8),((3),C("graphite")+O_(2) (g) rarr CO_(2)(g),-393.51),((4),CO(g)+1//2O_(2)(g) rarr CO_(2)(g),-282.98):}` |
|
Answer» Correct Answer - `-266.3` kJ/mol and `-824.2` kJ/mol (i) `Fe+1/2 O_(2) rarr FeO` `DeltaH=-155.8-393.51+282.98=-266.3" kJ mol"^(-1)` (ii) `2Fe+3CO rarr Fe_(2)O_(3)+3C` `DeltaH=-492.6+848.94-1180.53=824.19" kJ mol"^(-1)` |
|