From the following data, mark the option (s) where DeltaH is correctly written for the given reaction. Given: H^(+)(aq)+OH^(-) (aq) rarr H_(2)O(l)""DeltaH= -57.3 kJ DeltaH_("solution") of HA(g)= -70.7 kJ/mol Delta_("solution") of BOH(g)=20 kJ/mol DeltaH_("ionization") of HA=15 kJ/mol & BOH is a strong base

From the following data, mark the option (s) where DeltaH is correctly

1.	From the following data, mark the option (s) where DeltaH is correctly written for the given reaction. Given: H^(+)(aq)+OH^(-) (aq) rarr H_(2)O(l)""DeltaH= -57.3 kJ DeltaH_("solution") of HA(g)= -70.7 kJ/mol Delta_("solution") of BOH(g)=20 kJ/mol DeltaH_("ionization") of HA=15 kJ/mol & BOH is a strong base
Answer» `{:("Reaction",DeltaH_(R)" (kJ/mole)"),(HA(aq)+BOH(aq) rarr BA(aq)+H_(2)O,-42.3):}` `{:("Reaction",DeltaH_(R)" (kJ/mole)"),(HA(g)+BOH(g) rarr BA(aq)+H_(2)O,-93):}` `{:("Reaction",DeltaH_(R)" (kJ/mole)"),(HA(g) rarr H^(+) (aq)+A^(-)(aq),-55.7):}` `{:("Reaction",DeltaH_(R)" (kJ/mole)"),(B^(+)(aq)+OH^(-)(aq) rarrBOH(aq),-20):}` Solution :`HA(aq)+BOH(aq) rarr BA(aq)+H_(2)O` `DeltaH=-57.3+DeltaH_("ion")HA` `=-42.3` OPTION (A) correct `HA(g)+BOH(g) rarr BA(aq)+H_(2)O` `DeltaH=DeltaH_("solution")HA+DeltaH_("solution")BOH-57.3+15` `=-93` option (B) correct `HA(g) rarr H^(+) (aq)+A^(-) (aq)` `DeltaH=DeltaH_("solution")+DeltaH_("ions")=-55.7 kJ` option (C) is correct `:. BOH` is strong base `:. DeltaH_("ion")=0` `:. B^(+) (aq)+OH^(-)(aq) rarr BOH(aq) DeltaH=0`