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From the following data of DeltaH of the following reactions, C(s)+(1)/(2)O_(2)(g) to CO(g),DeltaH=-110 kJ and C(s)+H_(2)O(g) to CO(g)+H_(2)(g),DeltaH=132 kJ Calculate the mole composition of the mixture of steam and oxygen on being passed over coke at 1273 K, keeping the reaction temperature constant. |
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Answer» Solution :From the QUESTION we see that the first reaction is exothermic and the second ONE is endothermic. Thus, if a mixture of oxygen and steam `(H_(2)O)` is passed over coke and at the same time, the temperature does not change, the composition should be such that `DeltaH` of both the reactions are numerically EQUAL. In the first reaction, consumption of `1//2` "mole" of `O_(2)` evolves 110 kJ of energy, while in the second reaction, for 1 mole of steam `(H_(2)O)`, 132 kJ of energy is absorbed. `:. "mole"` of `O_(2)` needed to EVOLVE `132kJ=(0.5)/(110)xx132=0.6` `:. "mole"` ratio of `O_(2)` and steam `(H_(2)O)=0.6:1`. |
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