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From the following thermochemical equations {:(C_(2)H_(4)+H_(2) to C_(2)H_(6),,DeltaH=-32.7 kcal),(C_(6)H_(6)+3H_(2) to C_(6)H_(12),, DeltaH=-49.2 kcal):} Calculate the resonance energy of benzene. |
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Answer» Solution :`C_(6)H_(6)` has three isolated carbon-carbon DOUBLE bonds. `DeltaH` for hydrogenation of `C_(2)H_(4)`, with one double bond, but the given value is `-49.2 "kcal"` `:.` resonance ENERGY `=3xx(-32.7)-(-49.2)` `=-48.9 "kcal"`. |
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