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| 1. |
From the following values of E^@ drawn from the emf series, calculate standard emf and the equilibrium constant for the reaction Hg^(2+)+Hg leftrightarrow Hg_2^(2+) E_(Hg_2^(2+),Hg)^@=0.788V, E_(Hg^(2+),Hg_2^(2+))^@=0.92V |
| Answer» SOLUTION :`0.132 V, 1.72 TIMES 10^2` | |