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From the given circuit find the value of I. |
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Answer» <P> Solution : APPLYING Kirchoff.s rule to the POINT P in the circuit, The arrows pointing towards P are POSITIVE and AWAY from P are negative. Therefore, `0.2A-0.4A+0.6A-0.5A+0.7A-I=0` `1.5A-0.9A-I=0` `0.6A-I=0` `I=0.6A` |
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