1.

From the given circuit find the value of I.

Answer»

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Solution :
APPLYING Kirchoff.s rule to the POINT P in the circuit, The arrows pointing towards P are POSITIVE and AWAY from P are negative.
Therefore, `0.2A-0.4A+0.6A-0.5A+0.7A-I=0`
`1.5A-0.9A-I=0`
`0.6A-I=0`
`I=0.6A`


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