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From the given circuit, using a silicon BJT, what is the value of VBC?(a) 6.13 V(b) -6.13 V(c) 7 V(d) -7 VThis question was addressed to me in an internship interview.My question comes from BJT DC biasing topic in section BJT Biasing of Analog Circuits |
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Answer» RIGHT answer is (b) -6.13 V For explanation I WOULD say: Consider the BJT to be in SATURATION. Then IC=12-0.2/2.2k=5.36 mA And IB=12-0.8/240k=0.047 mA IBMIN=ICSAT/β=5.09/50=0.1072mA which is greater than above IB. Hence TRANSISTOR is in the active region. Thus IC=βIB. VBE=0.7V IB=12-0.7/240=47.08μA IC=50×47.08=2.354 mA VCE=VCC-ICRC=12-2.354*2.2=12-5.178=6.83V Hence VBC = 0.7-6.83 = -6.13V. |
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