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From the given data , calculate the energy of an electron in the second Bohr orbit of an excited hydrogen atom. |
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Answer» Solution :We have, `E_(1)=-2.18 xx 10^(-11)` erg THUS applying `E_(n)= (E_(1))/(n^(2))` `E_(2)= - (2.18 xx 10^(-11))/(2^(2)) = - 0.545 xx 10^(-11)` erg |
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