1.

From the given datacalculate the radius of the third orbit of a hydrogen atom.

Answer»

SOLUTION :we have `r_(1)= 0.53 xx 10^(-8) CM`
Thus APPLYING `r_(N)= n^(2) r_(1)` …(Eqn.4)
`r_(3)= 3^(2) xx 0.53 xx 10^(-8) cm`
`=4.77 xx 10^(-8) cm= 4.77Å`


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