1.

From the given figure: i) Calculate DeltaE for the reactionand energy of activation for the forward reaction and energy of activation for the backward reaction. ii) The dotted curve is in the presence of a catalyst, what is the energy of activation for the two reactions in the presence of the catalyst? iii) will the catalyst change the extent of the reaction?

Answer»

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Solution :i)For the uncatalysed reaction, represented by upper curve
Energy of the reaction `(E_(r))= 110 kJmol^(-1)`
Energy of the products `(E_(p)) = 100 kJmol^(-1)`
`therefore` Change in the internal energy `(DeltaE) = E_(p) -E_(R )`
`=140-110=30kJmol^(-1)`
Energy of activation for the reverse reaction `(E_(a)(f) = E^(0)-E_(p)`
`140-100 = 40 kJ MOL^(-1)`
ii) For the catalyst reaction, represented by lower curve,
`E_(a)(f) = E^(0) - E_(r) = 120-110 = 10 kJmol^(-1)`
`E_(a)(b) = E^(0)-E_(p) = 120-100 = 20 kJmol^(-1)`
iii) There will no effect on the EXTENT for the reaction because the activation energies for the FORWARD reactions have decreased EQUALLY.


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