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From the given figure the length of hypotenuse AC and the perimeter of ABC |
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Answer» Answer: In ∆ABC, ∠B = 90° , and L(BC) = 21, and l(AB) = 20 ∴ According to Pythagoras’ theorem, ∴ l(AC)2 = l(BC)2 + l(AB)2 ∴ l(AC)2 = 212 + 202 ∴ l(AC)2 = 441 + 400 ∴ l(AC)2 = 841 ∴ l(AC)2 = 292 ∴ l(AC) = 29 Perimeter of ∆ABC = l(AB) + l(BC) + l(AC) = 20 + 21 + 29 = 70 ∴ The length of hypotenuse AC is 29 UNITS, and the perimeter of ∆ABC is 70 units.Read more on Sarthaks.com - https://www.sarthaks.com/863375/from-the-given-figure-find-the-length-of-hypotenuse-ac-and-the-perimeter-of-abc |
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