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From the output characteristic shown in fig.calculate the value of current amplification factor of the transistor when V_(CE)=2 V. |
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Answer» Solution :From the GIVEN CHARACTERISTIC, corresponding to `V_(CE)=2.0V`, note the collector current for two base current (SAY `50muA` and `200muA)`. The corresponding values of` I_c` are `3.0mA` and `9.0mA` RESPECTIVELY. Then `DeltaI_c=9-3=6mA, DeltaI_b=200-50=150muA` `:.` Current amplification FACTOR, `beta_(ac)=(DeltaI_c)/(DeltaI_b)=(6mA)/(150muA)=40` |
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