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From the output characteristic shown in fig.calculate the value of current amplification factor of the transistor when V_(CE)=2 V.

Answer» <html><body><p></p>Solution :From the <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> <a href="https://interviewquestions.tuteehub.com/tag/characteristic-914243" style="font-weight:bold;" target="_blank" title="Click to know more about CHARACTERISTIC">CHARACTERISTIC</a>, corresponding to `V_(CE)=2.0V`, note the collector current for two base current (<a href="https://interviewquestions.tuteehub.com/tag/say-1195451" style="font-weight:bold;" target="_blank" title="Click to know more about SAY">SAY</a> `50muA` and `200muA)`. The corresponding values of` I_c` are `3.0mA` and `9.0mA` <a href="https://interviewquestions.tuteehub.com/tag/respectively-1186938" style="font-weight:bold;" target="_blank" title="Click to know more about RESPECTIVELY">RESPECTIVELY</a>. <br/> Then `DeltaI_c=9-3=6mA, DeltaI_b=200-50=150muA` <br/> `:.` Current amplification <a href="https://interviewquestions.tuteehub.com/tag/factor-458892" style="font-weight:bold;" target="_blank" title="Click to know more about FACTOR">FACTOR</a>, `beta_(ac)=(DeltaI_c)/(DeltaI_b)=(6mA)/(150muA)=40`</body></html>


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