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From the point 15m away from the foot of the pole of height 50m the angle of elevation to the top of the pole is |
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Answer» Answer: Answer Let the height of the pole be h and the distance between the pole and tower be x. It can be OBSERVED that, tan60 ∘ = x
3
= x 50
x= 3
50
And, ∘ = x 50−h
1= x 50−h
50−h=x 50−h= 3
50
h=50− 3
50
h= 3
50( 3
−1)
h=21.1m Therefore, the height of the pole is 21.1m. |
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