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From the previous problem, find anequation for the speed of the ball at thedetermined location, assuming the ballstarts rolling from rest. |
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Answer» The kinetic energy of the ball consists of translational and rotational kinetic energy. Using conservation of energy we can solve for the speed of the ball. Therefore, mgh1 = mgh3+(1/2)m(VG)2+(1/2)IGw2, where m is the mass of the ball, VG is the velocity of the center of mass of the ball, w is the angular velocity of the ball, and IG is the rotational inertia of the ball about its center of mass. For no slipping w = (VG)/R, where R is the radius of the ball. And IG = (2/5)mR2. Combining these three equations we can solve for VG. Answer: VG = [(10g/7)(h1−h3)]1/2 |
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