1.

From the previous problem, find anequation for the speed of the ball at thedetermined location, assuming the ballstarts rolling from rest.

Answer»

The kinetic energy of the ball consists of translational and rotational kinetic energy. Using conservation of energy we can solve for the speed of the ball. Therefore, mgh1 = mgh3+(1/2)m(VG)2+(1/2)IGw2, where m is the mass of the ball, VG is the velocity of the center of mass of the ball, w is the angular velocity of the ball, and IG is the rotational inertia of the ball about its center of mass. For no slipping w = (VG)/R, where R is the radius of the ball. And IG = (2/5)mR2. Combining these three equations we can solve for VG.

Answer: VG = [(10g/7)(h1−h3)]1/2



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